Saturday, September 28, 2019

Questions From Number System Kerala PSC


1.       Find the decimal equivalent of 1010101
A)     75
B)      85
C)      1010101
D)     101010
Option B 85
Explanation: 1010101
1*26=64
0*25=0
1*24=16
0*23=0
1*22=4
0*21=0
1*20=1
64+0+16+0+4+0+1=85

2.       If 110011002 is divided by 1102 the quotient is
A)     11011
B)      1111
C)      100010
D)     100001
3.       The given hexadecimal number (1E.53)16 is equivalent to ____________
a) (35.684)8
b) (36.246)8
c) (34.340)8
d) (35.599)8
Answer: b
Explanation: First, the hexadecimal number is converted to it’s equivalent binary form, by writing the binary equivalent of each digit in form of 4 bits. Then, the binary equivalent bits are grouped in terms of 3 bits and then for each of the 3-bits, the respective digit is written. Thus, the octal equivalent is obtained.
(1E.53)16 = (0001 1110.0101 0011)2
= (00011110.01010011)2
= (011110.010100110)2
= (011 110.010 100 110)2
= (36.246)8


1.       In hexadecimal system E stands for        
A.      5
B.      14
C.      2
D.      15
Ans is Option B : 14
A=10
B=11
C=12
D=13
E=14

The last number  of octal number system
 

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